# Understanding Horse Power in the Automotive World

Horse power *and torque are several terms that describe how much work a vehicle engine or other source does to do something over a certain period of time.*

In the automotive world, *house power* and torque are one of the important elements in a car. For more details, here is some information about *house power * and torque.

**Understanding Horse Power**

The term *Horse Power*(HP) in this engine (horsepower unit) was first introduced by an engineer in Scotland. He explained that ponies have an average ability to carry a load of 550 *pounds* or the equivalent of 249.4 kilograms over a distance of 30.48cm in one second. *Well,* the weight of 550 *pounds* is then multiplied by 60 seconds to produce a figure of 33,000 *foot pounds* / *minute. *Then furthermore this finding will be used as the basic basis of the size of 1 HP or 1 *horse power* (horse power).

**Definition of Torque**

So, this horsepower can be summed up as a force needed to rotate an object on its axis. So, the existence of this torque has a very important meaning in order to move a motorized vehicle from rest, to moving or speeding. The size of the torque on this machine also has an influence on the acceleration of changes in the location of a vehicle from one point to another. Torque can also be referred to as a measure of the power produced by the vehicle engine.

**Functions of Horse Power and Torque**

Based on the above understanding, it can be concluded that the existence of torque and horsepower is closely related even though both have differences. *Horse power* is needed to keep the speed of the vehicle faster and faster, while torque is needed by the engine to be able to move which will then produce horse power.

**Torque and Power Relationship to Acceleration Ability**

Keep in mind again that torque and horsepower are two different things, but have a relationship with each other. Apparently, the greater the impact on the shorter acceleration time. The explanation is that up and down torque can still be manipulated or changed by the gearbox, while the amount of power is purely the result of engine performance. This torque can increase further based on the calculation of the gear ratio. For example, a torque of 50 *pound feet* with a gear ratio of 3.0 will result in a torque of 150 *pound feet*or three times the starting torque of the engine. This is what is felt by the driver who is increasingly pushed back into the back of the seat when stepping on the gas. In a CVT transmission that adjusts the gear ratio constantly by always maintaining power at its peak, it can accelerate faster than manual. To produce a fierce acceleration, engine power can be combined with an aggressive gear ratio.

**How to Increase Your Own Car ***horse Power*

*horse Power*

- Replacing the Computer Chip (ROM) on the
*Engine Control Unit*(ECU) of your car. Enough to increase the car's HP but not too significant without the installation of an air filter and exhaust modifications and the addition of a turbo, and others. - Modify the exhaust system (muffler). Installing a barrier-free exhaust or
*free flow*can increase engine power by 5-10 HP. - Installing the Turbocharger. Usually accompanied by adding a larger cylinder size so that the intake of oxygen is greater into the engine so that the combustion process is more optimal.
- Installing a larger air filter. A larger air filter will increase the amount of air that enters the engine so that the engine will be more optimal.
- Reduce car weight. Remove things that are not really needed from the car or from the car
*spare parts*so that the car is lighter and the power that comes out will be more optimal. - Replace spark plugs and fuel. Iridium spark plugs will make the engine power better and the car run faster. Fuel with high octane affects engine performance better. Choose lead-free fuel such as Pertamax Plus or its equivalent so that there is no residue on the engine so that the engine remains clean and provides maximum performance.
- Install a current stabilizer.

**How to Calculate Torque and Horse Power**

**Torque**

The torque formula is actually very simple, namely force x distance. If a force F (Kg) is applied to a rotation that has a length of r (m) to tighten the bolt, then the torque used is Fr (kg m). Torque changes (first reduction and speed reduction are carried out by the gear box) as shown in the figure if torque F acts on gear A (with radius r) associated with gear B (with radius 2r) torque on gear A; TA = TF x r. torque on gear B ; TB = F x 2r. the more the number of teeth on the gear the greater the torque that occurs so that the speed is reduced to half.

**State in the Machine**

The length of rotation (r) is equal to the distance from the *crankshaft* to the *crank pin*. this is half the stroke of the piston. The force (F) exerted on the swivel is equal to the compression pressure produced by the combustion gases which will push the piston down. Therefore the torque (T) changes according to the magnitude of the force (F) as long as r remains. The magnitude of the force F, which changes according to changes in engine speed, means that it is affected by the combustion efficiency as well as T also changes.

*house Power*

*house Power*

Average work is measured in terms of final power (the torque from the *crankshaft* drives the motorcycle but this is only the force to move the motorcycle and the speed at which the motorcycle moves does not account for power is the speed at which work is done). Labor = work/time = kg.m/sec. (work per second)

**Energy Unit**

PS ( *prerd strarke in Germany* ) 1 PS – 75 Kg m/sec is the power to move an object weighing 75 kg as far as one meter in one second (the greater the power, the greater the amount of work per unit time).

*crankshaft* Power Calculation

*crankshaft*Power Calculation

It is preferable to count the number of times the crank pin moves by a specific force per unit time (seconds). Work Q = force F x distance S Torque T = force F x distance, r : F = T/r Distance S traveled by the crank pin per minute = 2p.Rn Power = work/time/second 1PS = 75 Kg.m/ sec ( 735.49 W ) Q = FS = T/r x2π r N = 2π NT Power (PS) = 2π NT/60 x 75 = NT/716 = 0.0014NT (Unit of work)